What is the work done by friction on a sliding box?

AI Thread Summary
The discussion revolves around calculating the work done by friction on a sliding box with a mass of 12 kg and an initial speed of 10 m/s as it encounters a rough surface with a friction force of 72 N over a distance of 3.0 m. To find the work done by friction, the formula Work = Force x Displacement is applied, leading to a calculation of 216 Joules. Additionally, the velocity of the box after leaving the rough surface and the distance required to bring the box to a complete stop are also inquired about. The net force and acceleration are calculated, but there is uncertainty regarding the accuracy of the acceleration value. The discussion highlights the importance of understanding work and friction in physics problems.
tiffanyg
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1. a box of mass 12 kg slides at a speed of 10 m/s acros a smooth level floor, where it enters a rough portion 3.0 m in length. In the rough portion, the box experiences a horizontal friction force of 72N.

a) how much work is done by the frictional force?
b) what is the velocity of the box when it leaves the rough surface?
c) what length of rough surface brings the box coompletely to rest?

Since, I got stuck in the first question...i tried this:

F net= ff+fn
fnet = 72 n+ mg

fnet= 189.6 n

fnet/m = a

a= 15.8 ---> i don't know if a is right...
 
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Ok the first part asks how much work is being done. Work is normally measured in Joules. Try the equation Work = Force x Displacement .
 
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