Forces on a weight stack pulling horizontally

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Homework Help Overview

The discussion revolves around the forces acting on a weight stack in a pulley system, particularly when the puller is moving horizontally. Participants are exploring the application of the formula F=mg in this context.

Discussion Character

  • Exploratory, Assumption checking, Conceptual clarification

Approaches and Questions Raised

  • Participants are questioning the validity of using F=mg for a horizontally moving puller and discussing the implications of the pulley system on force calculations. There are considerations about the relationship between the distance the rope is pulled and the weight lifted.

Discussion Status

Some participants have provided guidance on the assumptions made regarding the forces involved, while others are exploring the complexities introduced by the pulley system. There is an acknowledgment of the need to consider additional factors when calculating work and power.

Contextual Notes

There are references to attachments that may provide visual context, but the lack of a diagram initially complicates the discussion. The thread has been moved to the Homework Help forums, indicating a focus on academic inquiry.

llhalsey
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Forces on a weight stack with the position of the pulleys so the weight is pulled up and the puller is moving a horizontally. Is it correct to use F=MG?
 
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llhalsey said:
Forces on a weight stack with the position of the pulleys so the weight is pulled up and the puller is moving a horizontally. Is it correct to use F=MG?

Without a diagram it's hard to say for sure, but if I'm picturing it correctly, I think the answer is yes.
 
See attachment :)
 

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  • dog pulling.jpg
    dog pulling.jpg
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llhalsey said:
See attachment :)

The force on the horizontal rope has to support the weight of the object, so your assumption is correct. However, if you start moving the weight up or down, the pulley system has to factor into any other calculations (work, etc.).

BTW, I've moved this thread to the Homework Help forums, where all schoolwork-type questions should be posted.
 
I note that there are two lines from the weight to the pulley. That means that you will have to pull the rope on the left twice the distance you lift the weight.
 
SO to calculate work = FD is it as simple as the distance the rope is pulled * mass of the wt *g. and Power would be divided by the time it takes to pull the distance or is there something specific with a pulley system that needs to be take into account?
 

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