- #1
pedro_bb7
- 11
- 0
Hello, I got a problem using Fourier series.
f(x) = sin(2x)*(x^2) (-pi < x < pi)
I got this answer, although it seems to be wrong.
f(x) = (-16/9)*sin(x) + (-1/8)*sin(2x) + sum((2*(-1)^n/(2-n)^2 - 2*(-1)^n/(2+n)^2)*sin(nx) , n, 3, 100)
f(x) = sin(2x)*(x^2) (-pi < x < pi)
I got this answer, although it seems to be wrong.
f(x) = (-16/9)*sin(x) + (-1/8)*sin(2x) + sum((2*(-1)^n/(2-n)^2 - 2*(-1)^n/(2+n)^2)*sin(nx) , n, 3, 100)