Fourier transform of a gaussian

sleventh
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fourier transform of the gaussian (1/\sqrt{2 pi \sigma}) e ^ (^{x^2/2\sigma^2})



now the Fourier of a gaussian is said to equal another gaussian as shown by equation (4) here:
http://mathworld.wolfram.com/FourierTransform.html

but when i also did it using equation (1) here:
http://mathworld.wolfram.com/FourierTransform.html

i find a completely different answer.

im wondering how i am doing the calculations wrong using the normal definition of Fourier transforms.

fourier transforms are very new to me so any help is much appreciated thank you.
 
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you'll have more chance if you show you working, its pretty hard to guess what you're doing wrong
 
setting a=1/2 \sigma ^2 and k=1/2\sqrt{2 pi sigma} i use the concept the Fourier of a gaussian equals another gaussian and am given
\sqrt{2 sigma ^2 pi} e^((-2pi^2 \sigma^2 / \sqrt{2 pi sigma}
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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