Fourier Transform: Show g(hat)(xi) = e-i*xi.a * f(hat)(xi)

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Homework Statement


Suppose that f has Fourier transform f(hat). If a is a member of Rn, let g be the function defined by g(x) = f(x-a). Show that g(hat)(xi) = e-i*xi.a * f(hat)(xi).

Homework Equations





The Attempt at a Solution


Is it using the convolution theroem otherwise I am lost.
 
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Write down your definition of Fourier transform. Then just apply the change of variable x-a=u. Nothing to do with convolution.
 
Thanks. Now I'm looking to solve ut + v . div(u) = D*laplacian(u), x is a member of Rn, t > 0,
u(x,0) = 0, x is a member of Rn, (This is of course a Cauchy problem) where v is a member of Rn and is the constant velocity vector of the medium. D is constant diffusivity.
I can find the Fourier transform of D*laplacian(u) which is -|xi|2*u(hat)(xi) and the Fourier transform of ut is u(hat)(xi) but how do I find the Fourier transform of the other part. I think we use the Fourier transform of g(hat)(xi) but I'm not sure.
 
I still don't even know where to start on the final integral.
 
I know that the Fourier transform of grad(u) = i*u(hat)(xi)*(xi1+xi2+...+xin) and v is a constant vector so the Fourier transform of v.grad(u) = v.(i*u(hat)(xi)*(xi1+xi2+...+xin), is there anyway I can simplify this.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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