Calculate Fourier Transform of (1+at^2)^-n

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The discussion focuses on calculating the Fourier transform of the function (1+at^2)^-n, where n is a natural number greater than 1 and a is a positive number. Participants suggest using contour integration and the Residue Theorem for specific small values of n, such as 2, 3, and 4, to establish a pattern. There is a consensus that while specific cases can be solved, finding a generalized solution for all n remains challenging. The conversation emphasizes starting with simpler cases to build towards a broader expression. Overall, the goal is to derive a comprehensive formula for the Fourier transform of the given function.
kbrijesh
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how to get the Fourier transform of (1+at^2)^-n ? n is a natural number such that (n>1) and a is any positive number.

i.e. ∫((1+at^2)^-n)*exp(-jωt)dt; limits of integration goes from -∞ to ∞
 
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kbrijesh said:
how to get the Fourier transform of (1+at^2)^-n ? n is a natural number such that (n>1) and a is any positive number.

i.e. ∫((1+at^2)^-n)*exp(-jωt)dt; limits of integration goes from -∞ to ∞

You can do it via contour integration for specific small n but not sure for general n. But first, look at a simple case:

\int_{-\infty}^{\infty} \frac{e^{-i\omega t}}{(1+2t^2)^2}dt

Now that can be solved by the Residue Theorem. First get that one straight, then go on to n=3, maybe 4, then try and come up with an expression for the general case.
 
jackmell said:
You can do it via contour integration for specific small n but not sure for general n. But first, look at a simple case:

\int_{-\infty}^{\infty} \frac{e^{-i\omega t}}{(1+2t^2)^2}dt

Now that can be solved by the Residue Theorem. First get that one straight, then go on to n=3, maybe 4, then try and come up with an expression for the general case.



Yes, you are true. Even using contour integration we can do it upto n=3. But I am y\trying to get a generalized solution.

Anyway, thanks for your reply.