- #1

Pushoam

- 962

- 52

## Homework Statement

## Homework Equations

## The Attempt at a Solution

[/B]Assuming that the relation ## v = \omega r ## is valid in relativistic calculation.

As the speed is greater for higher kinetic energy, ## \omega_2 ## is greater.

This is shown by only (d). So, I think (d) should be the correct answer.

## K.E._2 = (\gamma_2 -1) m_p c^2 = m_p c^2 ##

## v_2 = \frac { \sqrt{ 3}} 2 c ##

Similarly, ## v_1 = 0.6 c ##

## \frac { \omega_1}{\omega_2} = \frac { v_1}{v_2} = \frac { 1.2}{\sqrt{ 3}} ##

## K.E._2 = (\gamma_2 -1) m_p c^2 = m_p c^2 ##

## v_2 = \frac { \sqrt{ 3}} 2 c ##

Similarly, ## v_1 = 0.6 c ##

## \frac { \omega_1}{\omega_2} = \frac { v_1}{v_2} = \frac { 1.2}{\sqrt{ 3}} ##

Is this correct?

#### Attachments

Last edited by a moderator: