Fresnel Lens - Solve for Lithography & Power

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SUMMARY

The discussion focuses on the calculations involved in using a Fresnel lens for lithography and power applications. The formula M = (lambda*f)/r_n was correctly applied, yielding a result of 29.48 nm. However, the subsequent calculation for focal length using f = r^2/(n*lambda) resulted in an unexpected power value of 2.56x10^03 diopters, indicating a potential error in the expression or assumptions made. Participants are encouraged to review the calculations for accuracy and clarity.

PREREQUISITES
  • Understanding of optical physics, specifically lens formulas.
  • Familiarity with unit conversion, particularly in the context of meters and nanometers.
  • Knowledge of Fresnel lens applications in lithography.
  • Basic grasp of diopter calculations and their significance in optics.
NEXT STEPS
  • Review the derivation of the Fresnel lens equations for lithography applications.
  • Study the implications of focal length on lens power in diopters.
  • Explore advanced optical simulation tools for lens design, such as Zemax or Code V.
  • Investigate common errors in optical calculations and how to avoid them.
USEFUL FOR

Optical engineers, physicists, and students involved in lens design or lithography processes will benefit from this discussion.

Schreiber__
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Homework Statement
Fresnel lens Part 1: You would like to design a 25 mm diameter blazed Fresnel zone plate with a first-order power of +1.5 diopters. What is the lithography requirement (resolution required) for making this lens that is designed for 550 nm? Express your answer in units of 𝜇𝑚 to one decimal point.

Fresnel lens Part 2: What would the power of the first diffracted order of this lens be at wavelength of 400 nm? Express your answer in diopters to one decimal point.
Relevant Equations
M = lambda/NA = (lambda*f)/r_n -> Part 1
f = r^2/(n*lambda) -> Part 2
For the first part, I got correct:
M = (lambda*f)/r_n
Converting units to meters (m) then plugging them in:
(550x10^-9 m) * (0.67 m)/(0.0125 m) = 2.948x10^-5 or 29.48x10^-6 m or 29.48 nm
This checked out.

For the second part, using the information from the first part:
f = r^2/(n*lambda) = (0.0125 m)^2/(1*400x10^-9m) = 390.625

To calculate the power in diopters we take 1/f = 1/390.625 = 2.56x10^03 ! This seems too small of a value.

I am missing something here or have used an incorrect expression.

Thanks for the help!
 

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