Friction on an incline and velocity

AI Thread Summary
A block with an initial velocity of 7.3 m/s slides up a frictional incline of 51.5 degrees, where the coefficient of kinetic friction is 0.1. The problem requires determining how far the block travels along the incline before stopping. The discussion emphasizes the transition from kinetic energy to gravitational potential energy, highlighting the role of friction as an external force that does negative work on the block. Key equations include the work-energy principle and the forces acting on the block, such as gravitational and frictional forces. Understanding the energy transformations and applying the correct equations will lead to the solution.
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Homework Statement


A block is sliding with an initial velocity of 7.3 m/s along a frictionless horizontal surface when it then goes up an incline of 51.5 degrees that does have friction. If the kinetic friction coefficient is 0.1 then how far along the incline (hypotenuse) will the object travel before it stops?
7-p-044.gif


Θ = 51.5°
µ(k) = 0.1
v(initial) = 7.3 m/s
v(final) = 0 ...because the question asks at what point will it stop, meaning there is no more speed.
g = 9.81
d = ?
m = ?
a = ? ...i do not know if i even need acceleration
F = ?
W = ?

Homework Equations


KE = W = 1/2mv(final) - 1/2mv(initial)
F = mg
W = Fd
Force up ramp... F = mg sinΘ
Normal Force against ramp... Fnormal = mg cosΘ
Force of friction between block and ramp... F(f) = µ Fnormal

The Attempt at a Solution


Honestly i have no clue where to even begin, i am so lost on this problem :(
Also, my equations could be wrong.
 
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Okay, Let's think about it together alright?

At the horizontal surface, There is no friction. So there is no change in kinetic energy Which mean there is no change in the total energy
But on the incline, I have an external force acting on it which is friction of course.
and work is W = f*d cos theta.
What does work do? if the work is positive then it adds energy to the object. If it is negative then it takes away energy.

Now think of the initial position and the final position, What kind of energy does the object have at these moments?

Hint: at the end of the movement, The velocity is zero and it is not at the ground level so there is height (What form of energy is that?)

Put it in an equation describing what happens to the total energy and volaaa you have solved it!
 
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Biker said:
Okay, Let's think about it together alright?

At the horizontal surface, There is no friction. So there is no change in kinetic energy Which mean there is no change in the total energy
But on the incline, I have an external force acting on it which is friction of course.
and work is W = f*d cos theta.
What does work do? if the work is positive then it adds energy to the object. If it is negative then it takes away energy.

Now think of the initial position and the final position, What kind of energy does the object have at these moments?

Hint: at the end of the movement, The velocity is zero and it is not at the ground level so there is height (What form of energy is that?)

Put it in an equation describing what happens to the total energy and volaaa you have solved it!

Okay i think i get what you're saying, so it starts with kinetic energy and ends with gravitational potential energy. But what equations, i don't know which ones i could use...
 
Well I know that
W = E2- E1
Substitute these values with what you have.
For example E1 should be kinetic energy.
 
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