Friction problem (mass on top of another mass)

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To determine the minimum coefficient of static friction for block 1 on block 2, the calculated value is 0.53, based on the friction force and normal force. For part (b), the coefficient of kinetic friction is half of the static friction value, resulting in 0.265. The user is unsure how to proceed with calculating the acceleration of block 1 with respect to the table and the forces involved in parts (c) and (d). A suggestion to draw free body diagrams for both blocks is made to clarify the forces acting on them. The discussion highlights the importance of understanding friction and acceleration in a two-block system on a frictionless table.
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a block with mass m1=4.0kg is placed on top of a block with mass m2=12.0kg.
(a) if the acceleration of the lower block is a2=5.2m/s^2, calculate the minimum coefficient of static friction (u minimum, where u is mew), for the contact surface between 1 and 2, that will prevent block 1 from slipping with respect to block 2.
(b) the contact surfaces are polished and it is found that block 1 now slides on block 2. if the coefficient of kinetic friction uk=1/2u(minimum), u(minimum) found in a, what is the acceleration of block 1 with respect to the table (a1).
(c) what is the acceleration of block 1 with respect to the acceleration of block 2?
(d) what force must be applied to block 2 in (a) and (b) if the table is frictionless
image_2Nj40.jpg

im stuck on a, i don't know what to do with the acceleration, i thought about multiplying it with one of the masses, but i don't know which one
 
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Draw free body diagrams for both the blocks. What forces are acting on each of them?
 
for (a) i found the Ff of m1 by:
Ff = ma
Ff = 4(5.2)
Ff = 20.8
mew (u) = Ff/Fn
u = 20.8/(4)(9.8)
u = 0.53

so for (b) the u k = 1/2 (0.53) = 0.265

am i right for (a)? and (b), I've no idea how to start
 
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