- #1
gracy
- 2,486
- 83
in this video question no 5 actually it is first question of the video but it's number is 5,i didn't understand this question.first i thought The force acting on block A is its weight in vertically downward direction, with no friction with the wall and Condition for equillibrium: Sigma Fx= 0, Sigma Fy= 0, & Sigma Fz= 0, Hence ,a vertical force can never be balanced by a horizontal force, whatever it (applied force) is, even infinity. Only friction force b/w wall and block A can balance weight of A. But here there is no friction b/w block A and the wall. Hence , option (d) is correct.but then i thought friction force is not necessarily be horizontal it just opposes motion in whichever direction ,so why it can't balance normal force and what about friction force between A &B ,it is especially mentioned in the question coefficient of friction between block b and a so won't it be used in the solution of problem?