Frictional Forces: Paper & Object on Top

  • Thread starter Thread starter grief
  • Start date Start date
  • Tags Tags
    Forces
AI Thread Summary
When pulling a piece of paper with a massive object on top, the force exerted is primarily on the paper, but it also affects the object through friction. If the paper is stationary, the force is determined by the static coefficient of friction multiplied by the weight of the object above. If the paper is in motion, the dynamic coefficient of friction applies, along with any additional force from the object's acceleration. Abruptly pulling the paper increases the total force due to both the friction with the surface and the friction between the paper and the object. The acceleration of the mass is linked to the acceleration of the paper as long as the mass remains in contact and does not slide.
grief
Messages
73
Reaction score
1
if I have a pieace of paper, a massive object resting ontop of it, and I pull the paper, am I exerting a force only on the paper or on the object on top of it? Or does the object on top have only friction acting on it?
 
Physics news on Phys.org
You are exerting a force directly on the paper, and that force will equal the force which is the sum of forces of friction between the paper and the table, which is related to the mass on top of the paper.

If the paper is not moving then the force will be given by the product of static coefficient of friction (between paper and surface supporting it) and the weight on the paper. If the paper is moving then it will product of dynamic coefficient of friction (between paper and surface supporting it) and the weight on the paper, plus the product of the mass and whatever acceleration is applied to the mass. If the paper is pulled abruptly, the force will be the sum of the friction between the paper and supporting surface and the friction between paper and mass.
 
If the paper is moving then it will product of dynamic coefficient of friction (between paper and surface supporting it) and the weight on the paper, plus the product of the mass and whatever acceleration is applied to the mass.

so when you say the acceleration applied to the mass, is that the same as the acceleration applied on the paper?
 
grief said:
so when you say the acceleration applied to the mass, is that the same as the acceleration applied on the paper?
In the case where the mass remains in contact with the paper, and does not move with respect to the paper.
 
TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
Thread 'Variable mass system : water sprayed into a moving container'
Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
Back
Top