Fridge on Truck Homework: Find Normal Force, Forces Exerted & Rope Tension

  • Thread starter Thread starter ledphones
  • Start date Start date
  • Tags Tags
    fridge Truck
AI Thread Summary
The discussion revolves around a physics homework problem involving a refrigerator on a truck. The normal force exerted on the refrigerator by the truck bed is calculated to be 1274 N when the truck is stationary. When the truck accelerates at 3 m/s², the horizontal force on the refrigerator is 390 N. The maximum acceleration before the refrigerator tips over is derived using torque equations, but the initial attempt was incorrect. Lastly, the tension in the rope connecting the refrigerator to the truck cab is analyzed under conditions of increased acceleration, requiring further calculations involving torque.
ledphones
Messages
17
Reaction score
0

Homework Statement



A refrigerator is approximately a uniform parallelepiped h = 8 ft tall, w = 3 ft wide, and d = 2 ft deep. It sits upright on a truck with its 3 ft dimension in the direction of travel. Assume that the refrigerator cannot slide on the truck and that its mass is 130 kg. For the first three parts of this problem, the rope shown in the picture is not there.
a) When the truck is not accelerating, what is the normal force exerted on the refrigerator by the truck bed?

N = N *
1274 OK
b) If the truck now accelerates at 3 m/s2, what is the horizontal force exerted on the refrigerator by the truck bed?

f = N *
390 OK
c) What is the maximum acceleration the truck can have such that the refrigerator does not tip over?

amax = m/s2
d) Suppose now that a rope connects the top of the refrigerator with the cab of the truck, which now accelerates at twice the acceleration calculated in (c). The refrigerator lifts off slightly at the front but is held in place by the horizontal rope. Find the tension in the rope.

Homework Equations





The Attempt at a Solution



for c) Στ=0 for the fridge to not fall
Στ=m*a*R*h/w-m*g*R*w/h
a=g
a=9.81 m/s^2

this is wrong

for d) i believe i have to set my answer up like this
Στ=0 for the fridge to not fall
Στ=m*a*R*h/w-m*g*R*w/h-T*2*R*h/w
 
Physics news on Phys.org
c)

g/h=a/w

If you draw a sketch of the body it's evident. The total acceleration (g and a) vector points to an edge.
 
Thread 'Collision of a bullet on a rod-string system: query'
In this question, I have a question. I am NOT trying to solve it, but it is just a conceptual question. Consider the point on the rod, which connects the string and the rod. My question: just before and after the collision, is ANGULAR momentum CONSERVED about this point? Lets call the point which connects the string and rod as P. Why am I asking this? : it is clear from the scenario that the point of concern, which connects the string and the rod, moves in a circular path due to the string...
Back
Top