Galvanometer to ammeter/voltmeter

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SUMMARY

The discussion focuses on converting a galvanometer with a resistance of 25 ohms and a full-scale deflection current of 500μA into an ammeter and a voltmeter. For the ammeter conversion to 20mA full scale, the shunt resistance is calculated to be 0.641 ohms using the formula Rsh = (RG * Ifs) / (Ia - Ifs). For the voltmeter conversion to 500mV full scale, the series resistance is computed to be 975 ohms using the equation VV = Ifs(Rsh + Rh).

PREREQUISITES
  • Understanding of galvanometer principles
  • Knowledge of Ohm's Law (V=IR)
  • Familiarity with shunt and series resistance calculations
  • Basic electrical circuit analysis skills
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  • Study the principles of shunt resistors in ammeter design
  • Learn about series resistors in voltmeter applications
  • Explore advanced circuit analysis techniques
  • Review practical applications of galvanometers in modern electronics
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Electronics students, electrical engineers, and hobbyists interested in circuit design and measurement techniques will benefit from this discussion.

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Homework Statement



The resistance of a galvanometer coil is 25ohms and the current required for full scale deflection is 500μA.
a) explain how to convert the galvanometer to an ammeter reading 20mA full scale, and compute the shunt resistance
b) explain how to convert the galvanometer to a voltmeter reading 500mV full scale, compute the series resistance

Homework Equations



V=IR
IfsRG= (Ia-Ifs)Rsh
Rsh=(RGIfs)/(Ia-Ifs)

The Attempt at a Solution

RG=25ohms

a)
does Ifs=0.02 or 0.0005A

0.0005A * 25ohms = ( 0.02A- 0.0005A) Rsh ??
Rsh=0.641

b)
 
Last edited:
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Your value for (a) looks okay. How will you approach (b)?
 
idk VV=Ifs(Rsh+Rh)
 
(0.5/0.0005) -25 = 975 ?
 
Looks good.
 
cool beans
 

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