Gamma Function Limits: Proving \Gamma(x) \to 0 as x \to -\infty

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Homework Help Overview

The discussion revolves around the behavior of the gamma function, specifically its limit as \( x \) approaches negative infinity. Participants are exploring how to demonstrate that the absolute value of the gamma function tends to zero in this context.

Discussion Character

  • Exploratory, Assumption checking, Conceptual clarification

Approaches and Questions Raised

  • The original poster attempts to use Gauss's Formula to analyze the gamma function's behavior, questioning whether this is the best approach. Other participants suggest examining the graph of the gamma function for insights and discuss the implications of poles on the negative integers.

Discussion Status

Participants are actively engaging with the problem, with some suggesting modifications to the original question to exclude poles. There is a recognition of the complexity involved, and one participant expresses a potential new direction for solving the problem without relying on Gauss's Formula.

Contextual Notes

There is a discussion about the poles of the gamma function at non-positive integers, which may affect the approach to proving the limit. The original poster considers defining a modified function to avoid these poles.

julypraise
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Homework Statement



The absolute value of the gamma function \Gamma (x) that is defined on the negative real axis tends to zero as x \to - \infty. Right? But how do I prove it?

Homework Equations


The Attempt at a Solution



I've tried to use Gauss's Formula:

\Gamma(x)=\lim_{n\to\infty}\frac{n!n^{z}}{z(z+1) \cdots (z+n)}.

Should I keep going in this direction?

But frankly, the calculation gets too technical so it'd be better if there is a bit easier way.
 
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julypraise said:

Homework Statement



The absolute value of the gamma function \Gamma (x) that is defined on the negative real axis tends to zero as x \to - \infty. Right? But how do I prove it?



Homework Equations





The Attempt at a Solution



I've tried to use Gauss's Formula:

\Gamma(x)=\lim_{n\to\infty}\frac{n!n^{z}}{z(z+1) \cdots (z+n)}.

Should I keep going in this direction?

But frankly, the calculation gets too technical so it'd be better if there is a bit easier way.

Have you ever looked at the graph of the Gamma function on the real line? Look in here:
http://en.wikipedia.org/wiki/Gamma_function . Does it look to you that ##\Gamma(x) \rightarrow 0 ## as ##x \rightarrow -\infty?##

RGV
 


Ray Vickson said:
Have you ever looked at the graph of the Gamma function on the real line? Look in here:
http://en.wikipedia.org/wiki/Gamma_function . Does it look to you that ##\Gamma(x) \rightarrow 0 ## as ##x \rightarrow -\infty?##

RGV

Ah.. I know what you mean. Maybe I need to modify my problem first. I know it has poles on non-positive integers. But excluding poles, it seems the absolute value of the gamma function tends to zero as x \to - \infty.

(http://en.wikipedia.org/wiki/File:Complex_gamma_function_abs.png)

May I define

f(x) = \Gamma (x) only for x<0 \quad \mbox{and} \quad x \neq -1, -2, -3, -4, \dots

and then prove |f(x)| \to 0 as x \to - \infty?
 


Ah... MY BAD! sorry.. what was I thinking... Let me clarify once more:

Take x_{n} \in (-n,1-n). Then \Gamma (x_{n}) \to 0 as n \to \infty.

I think I have an idea to solve it without using Gauss's Formula. After I try, I will put on the thread.

Anyway thanks for reminding me.
 

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