Gas liquid contact in stripping column

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SUMMARY

The forum discussion focuses on the mathematical derivation of gas-liquid contact equations in a stripping column, specifically transitioning from equation (1) to equation (2). The equations involve variables such as x[Ain], x[Aout], and S, with the final result expressed as \(\frac{x[Ain]-x[Aout]}{x[Ain]} = \frac{S - S^{n+1}}{1 - S^{n+1}}\). Participants clarify the correct use of summation indices and provide insights into the manipulation of the equations, emphasizing the importance of proper notation in LaTeX formatting.

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  • Familiarity with mathematical notation and LaTeX formatting
  • Knowledge of summation notation and its application in equations
  • Basic principles of stripping column operations
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RAfAEL_SP
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[itex]\frac{x[Ain]-x[Aout][/SUB][/SUB]}{x[Ain]-x[out][/SUB][/SUB]}[/itex]=[itex]\frac{\sum s^{K}-1}{\sum s^K}[/itex] (1)

for k = 0 to n

Final result:

[itex]\frac{x[Ain]-x[Aout][/SUB][/SUB]}{x[Ain]-x[/SUB][/SUB]}[/itex] = [itex]\frac{{S-S^{n+1}}}{1-S^{n+1}}[/itex]

(2)

Does anyone know how to get from (1) to (2).
 
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Hi RAfAEL_SP! Welcome to PF! :smile:

(use _ not SUB in latex, and use tex rather than itex for fractions that ou don;t want to be too tiny! :wink:)
c said:
[tex]\frac{x[Ain]-x[Aout][/SUB][/SUB]}{x[Ain]-x[out][/SUB][/SUB]}[/tex]=[tex]\frac{\sum s^{K}-1}{\sum s^K}[/tex] (1)

for k = 0 to n

Final result:

[itex]\frac{x[Ain]-x[Aout][/SUB][/SUB]}{x[Ain]-x[/SUB][/SUB]}[/itex] = [itex]\frac{{S-S^{n+1}}}{1-S^{n+1}}[/itex]

(2)

Does anyone know how to get from (1) to (2).

I think you mean [tex]\frac{\sum s^{K-1}}{\sum s^K}[/tex]
Then eg the denominator is (∑sK)/(1 - S) :wink:
 
The exponent is just k
 

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