[itex]\frac{x[Ain]-x[Aout][/SUB][/SUB]}{x[Ain]-x[out][/SUB][/SUB]}[/itex]=[itex]\frac{\sum s^{K}-1}{\sum s^K}[/itex] (1) for k = 0 to n Final result: [itex]\frac{x[Ain]-x[Aout][/SUB][/SUB]}{x[Ain]-x[/SUB][/SUB]}[/itex] = [itex]\frac{{S-S^{n+1}}}{1-S^{n+1}}[/itex] (2) Does anyone know how to get from (1) to (2).
Welcome to PF! Hi RAfAEL_SP! Welcome to PF! (use _ not SUB in latex, and use tex rather than itex for fractions that ou don;t want to be too tiny! ) I think you mean [tex]\frac{\sum s^{K-1}}{\sum s^K}[/tex] Then eg the denominator is (∑s^{K})/(1 - S)