Gas Tank Leak Rate Problem: Modeling and Calculating with V(t)=90(1-t/18)^2

xdeanna
Messages
24
Reaction score
0
The gas tank of a parked pickup truck develops a leak. The amount, V, in liters, of gas remaining in the tank after t hours can be modeled by the function
V(t)= 90(1-t/18)^2 , t is between 0 and 18.

b) how fast is the gas leaking from the tank at t=12h

I tried V(12) and V'(12) but still didn't get the answer at the back of the book. Shouldn't it be the first derivative at t=12?
 
Physics news on Phys.org
xdeanna said:
The gas tank of a parked pickup truck develops a leak. The amount, V, in liters, of gas remaining in the tank after t hours can be modeled by the function
V(t)= 90(1-t/18)^2 , t is between 0 and 18.

b) how fast is the gas leaking from the tank at t=12h

I tried V(12) and V'(12) but still didn't get the answer at the back of the book. Shouldn't it be the first derivative at t=12?

Yes, you should compute
\frac{dV}{dt}
and evaluating for t =12

You should get 3.33 l/h
 
Thanks :) I got that too.. the book is wrong
 
Prove $$\int\limits_0^{\sqrt2/4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx = \frac{\pi^2}{8}.$$ Let $$I = \int\limits_0^{\sqrt 2 / 4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx. \tag{1}$$ The representation integral of ##\arcsin## is $$\arcsin u = \int\limits_{0}^{1} \frac{\mathrm dt}{\sqrt{1-t^2}}, \qquad 0 \leqslant u \leqslant 1.$$ Plugging identity above into ##(1)## with ##u...
Back
Top