- #1
turnip
- 31
- 0
A catenary curve can be described by the following function:
y= a/2 (ex/a + e -x/a)
where a is a non-zero constant
By selecting sutable axes, devise an equation that will produce the gateway arch.
Right next to the question is a graph of an arch that is 630 feet high (on the y axis) and 630 feet long (on the x axis).
I have no idea where to start. I was thinking that I could substitute the x and y values in of 630 to find the a value and thus the normal function (since its constant). But then why not just ask for that? Why go and say devise an equation, i don't follow.
Please, I would really appreciate someone getting me started on this!
y= a/2 (ex/a + e -x/a)
where a is a non-zero constant
By selecting sutable axes, devise an equation that will produce the gateway arch.
Right next to the question is a graph of an arch that is 630 feet high (on the y axis) and 630 feet long (on the x axis).
I have no idea where to start. I was thinking that I could substitute the x and y values in of 630 to find the a value and thus the normal function (since its constant). But then why not just ask for that? Why go and say devise an equation, i don't follow.
Please, I would really appreciate someone getting me started on this!