Gauge Pressure problem (algebra based)

AI Thread Summary
The discussion centers on calculating gauge pressure at a depth of 100 m in water using the equation Pgauge = rho*g*h. The user seeks clarification on the variables, particularly the meaning of "rho," which represents the density of the liquid, typically denoted as 1000 kg/m^3 for water. The user correctly identifies g*h as the product of gravitational acceleration and height, which is essential for the calculation. The final solution provided is 980 kPa, demonstrating the application of the equation. Understanding these variables is crucial for solving similar problems in fluid mechanics.
guynameddanny
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Homework Statement


What is the gauge pressure at a depth of 100 m. in water?

Homework Equations


Pgauge = rho*g*h (or the pressure above atmospheric pressure)

The Attempt at a Solution



I missed a day of class (and on a summer class, that's a LOT of material). I am working problems that are assigned by the teacher over the internet. I'm sure these change of problems are things I can figure out, the problem I am having is understanding the equation for this problem. I can't seem to find where it talks about it in my book, I'm thinking because the teacher used either alternative symbols (because of limited keyboard characters), or he just likes to be different from the book.

I'm really just looking for help understanding the equation, what are the meanings of the different variables? I take it g*h is gravity*height (depth I presume), I'm not sure what "rho" would be though.

Edit: My theory is that "rho" is density of the liquid, not sure why he would use rho instead of something that makes sense like d.

To solve:

1000 kg/m^3 * 9.8 m/s^2 * 100 m = 980 kPa
 
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