Gauss: Conducting Spherical Shell w/ Point Charge

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SUMMARY

The discussion centers on calculating the electric flux through a spherical Gaussian surface surrounding a conducting spherical shell with a point charge at its center. The shell has a net charge of 3 μC and an inner radius of 0.8 m, while the Gaussian surface has a radius of 0.4 m. The correct approach involves applying Gauss's Law, which states that the electric flux is proportional to the enclosed charge. Since the Gaussian surface does not enclose any charge, the flux through it is zero, despite the initial calculations suggesting otherwise.

PREREQUISITES
  • Understanding of Gauss's Law in electrostatics
  • Familiarity with electric field equations, specifically E = (kQ)/r^2
  • Knowledge of surface area calculations for spheres, A = 4πr^2
  • Basic concepts of charge distribution in conductors
NEXT STEPS
  • Study Gauss's Law applications in electrostatics
  • Learn about electric field behavior inside conductors
  • Explore the implications of charge distribution on spherical shells
  • Review examples of calculating electric flux in various geometries
USEFUL FOR

This discussion is beneficial for physics students, educators, and anyone studying electrostatics, particularly those interested in the principles of electric fields and charge distributions in conductors.

calvert11
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Homework Statement


Consider a conducting spherical shell with inner radius 0.8 m and outer radius 1.3 m. There is a net charge 3 μC on the shell. At its center, within the hollow cavity, there is a point charge 3 μC.

Determine the flux through the spherical Gaussian surface S, which has a radius of 0.4 m. Answer in units of N · m2/C.

a= 0.8m
b= 1.3m
q1 = q2 = 3e-6 C

Homework Equations



Flux = E*A
E = (kQ)/r^2
A = 4pir^2

The Attempt at a Solution



I thought I could approach this in a very straight forward way: finding E of the point charge and multiplying it by the spherical shell's surface area (using the outer radius for both r's).

So, E = (8.99e9*3e-6)/1.3^2 = 15958.6
A = 4*pi*1.3^2 = 21.237

EA = 3.389e5 N*m2/C, which is wrong. I'm not sure what I should do.
 
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Your solution looks good to me. (Not sure why you used the outer radius, but it doesn't matter. For that matter, you could have just used Gauss's law directly.)
 

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