I have attached the problem
E*A = Qenc/ E0
The Attempt at a Solution
At the moment I am looking at the problem more conceptually and seeing what is happening at each point and I wanted to know If I was on the right track.
As all charge would reside on the outside of the inner conductor there would be no electric field
The electric field would be q/(2pi*r*E1*E0)
The electric field would be q/(2pi*r*E2*E0)
This is the part that has me puzzled , I thought the inner conductor charge(q) and outer conductor charge (-q) would cancel each other , so there would be no field present? Is this part mean to represent the outer rubber shielding of a coaxial cable?
Would the electric field also be zero outside of the cable due to the two charges cancelling?
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