Gaussian curvature for a given metric

mahdisadjadi
Messages
6
Reaction score
0

Homework Statement


Assume that we have a metric like:
<br /> ds^{2}=f dr^{2}+ g d\theta^{2}+ h d\varphi^{2}<br />

where r,\theta , \varphi are spherical coordinates.
f,g and h are some functions of r and theta but not phi.

Homework Equations


How can I calculate Gaussian curvature in r-theta, r-phi and theta-phi plane(2D)?
And also how for original metric(3D)?


The Attempt at a Solution

 
Last edited:
Physics news on Phys.org
@ HallsofIvy

Thanks!:smile:
 
After 1 month work on this problem, I found out following remarks:

1. If we tend to use "Brioschi formula" to calculate Gaussian curvature of a surface, we should embed it into a 2D space. For example, in the given metric, we should take r=constant to achieve a surface in theta-phi 2D space.

2. It we like to calculate Gaussian curvature of higher dimensional space, we can use Riemann Curvature Tensor and determinant of metric, as follows:
<br /> K=\frac{R_{1212}<br /> }{g}<br />
where g is determinant of metric matrix and R_{1212} is a component of Riemann Curvature Tensor. This K gives Gaussian curvature of the plane which is perpendicular to third axis.
 
I was kind of hoping we wouldn't have to calculate the Riemann tensor! Yes, the Brioschi formula only works for a two dimensional surface embeded in three dimensions- which was exactly your situation.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...

Similar threads

Back
Top