Gauss's Law Problem: Electric Field Inside a Charged Cylinder

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    Gauss's law Law
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To find the electric field inside a charged cylinder with a central wire, a Gaussian surface is used, considering the linear charge density of the wire and the cylinder. The electric field strength is derived as E = lambda / (2πr * permittivity constant), indicating that it depends on the distance from the wire. The confusion arises regarding the cancellation of the electric field from the hollow metal cylinder, which is explained by the fact that the Gaussian surface only encloses the wire, leading to no net charge contribution from the cylinder itself. Therefore, the electric field inside the cylinder is solely due to the wire's charge. Understanding this concept clarifies why the electric field does not cancel out completely inside the cylinder.
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Homework Statement


A long, thin straight wire w/ linear charge density lambda runs down the center of a thin, hollow metal cylinder of radius R. The cylinder has net linear charge density of 2lambda. Assume lambda is positive. Find an expression for the electric field strength inside the cylinder.

I used a cylinder of length L for my gaussian surface:

the charge inside is lambda * L

E*2pir*L = lambda * L / permittivity constant

E= lambda/ (2pi*r*permittivity constant)

This is correct, but the thing I don't see is how the electric field from the metal cylinder cancels inside the cylinder. Wouldn't it only cancel at the very center?


Homework Equations





The Attempt at a Solution

 
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Oh... if I draw a gaussian surface inside, it only encloses the wire. I'm trying to fit my head around this.
 
Could someone please give a good explanation for this? Thanks
 
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