General physics contest problems

AI Thread Summary
The discussion revolves around several physics contest problems, focusing on the behavior of charged particles in an electric field, the resolution capabilities of telescopes, and the dynamics of force and work in a system. For the first problem, the correct answer is identified as (a) y = d/2000, despite initial confusion about the choices. The second question about telescope resolution suggests that the larger mirror will allow for a resolution that is approximately 2.5 times smaller than Hubble's. In the third problem, the consensus is that the net force exerted by a person pulling a box at constant speed results in F = 0 and W ≠ 0, as the forces acting on the Earth and the box cancel each other out. Overall, the thread emphasizes the importance of understanding the underlying physics principles to solve these contest problems effectively.
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Homework Statement


A proton sits at coordinates (x; y) = (0; 0), and an electron
at (d; h), where d >> h. At time t = 0, a uniform electric
field E of unknown magnitude but pointing in the positive y
direction is turned on. Assuming that d is large enough that
the proton-electron interaction is negligible, the y coordinates
of the two particles will be equal (at equal time)
(a) at about y = d=2000;
(b) at an undetermined value since E is unknown;
(c) at about y = d=43;
(d) nowhere: they move in opposite directions.


Homework Equations


qE=F=ma


The Attempt at a Solution


I chose b, but the answer is a


Q2 Question 20
TheWebb space telescope, scheduled to be launched in 2010,
will have a mirror 6m in diameter. Compared with the Hubble
space telescope, whose mirror has a 2:4m diameter, it will
be able to resolve objects whose angular separation is about
(a) 2.5 times smaller;
(b) 5 times smaller;
(c) an order of magnitude smaller;
(d) the same: the larger mirror only increases the amount
of light gathered.

(no idea of telescope)

Q3
A person pulls a box along the ground at constant speed. Considering
the Earth and the box together as a system, which of
the following is true about the net force F exerted by the person
on this system and the work W she does on it?
(a) F = 0 and W = 0 ; (b) F != 0 and W = 0 ;
(c) F = 0 and W != 0 ; (d) F != 0 and W != 0 .

These are not homework problems, just contest prep. It would be great if someone can give me a sol'n as i have spend some time thinking about the problems already.

Thanks!
 
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q1, oops:blushing: , i don't understand the choices, what's "y=d=2000"?:confused:

q2. theta~=sin(theta)=lambda/a, a is the diameter of the lens. theta is the separation angle. so 2.5 times

q3. F=0, W=0 since she is exerting forces on Earth and the box at the same time and the two forces are of same magnitude but opposite direction. draw a fbd and you'll get it.:smile:
 
I have no idea whatsoever about telescopes. Could you go a bit step by step for #2? Thanks.

For #3, the answer is actually C, which confuses me too
 
heck I'm still puzzled why the answer to 1) isn't d. Can someone help me?
 
If an electric field E points in the positive x-axis, then proton will be moving up and electron down. They will meet
 
sorry postive y-axis
 
q3 is tricky, sorry for the mistake, W!=0 since the person does little work on the ground (or idealistically 0 work has been done on the ground). Why? think about it, the person is like walking so the friction exerted by his/her feet is discontinuous.

for q2, always try wikipedia first, there're plenty of info which will help u understand it much better. good luck on CAP ^_^
 
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