Solve for Force Exerted by Spring on Ball | General Physics Problem Help

AI Thread Summary
The discussion centers on solving a physics problem involving a spring and a ball in circular motion. The spring has a relaxed length of 1.0m and a spring constant of 200N/m, with a ball of mass 0.05kg attached, creating a new spring length of 1.4m. The initial calculation for the force exerted by the spring on the ball is determined to be 80N. The follow-up question involves finding the ball's speed, with a focus on using centripetal force equations. Participants clarify that the centripetal force formula, F = mv²/r, is essential for determining the velocity without needing the period.
sixstringartist
Messages
10
Reaction score
0
Im having difficulty with a physics problem and was looking for help.

The problem states: A spring has a relaxed length of 1.0m, when no force is acting to stretch or compress it. It has a spring constant k = 200N/m. A ball of mass .05kg is attached to one end and it is made to go in circle with radius 1.4m, the new length of the spring. Assume that gravity and air resistance can be igmored. What is the magnitude of the force exerted by the spring on the ball?

This I got: F_mag = k_s * delta s = 80N


The follow up problem is: For the ball in circular motion in the problem above, what is its speed.

This is what gets me. I don't know how to find velocity without knowing the period.

Any help is greatly appreciated.
 
Physics news on Phys.org
Hint: The motion is circular. What's the acceleration of the mass?
 
The centripetal force is equal to \frac{mv^2}{r}.
v:velcity
r:radius


Can you take it from there ?
marlon
 
marlon said:
The centripetal force is equal to \frac{mv^2}{r}.
v:velcity
r:radius


Can you take it from there ?
marlon

yes that's it! thank you! It all makes sense, b/c all I could find is v^2 = G *(M/R) for orbiting bodies which is basically the same formula. Thanks again.
 
TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
Thread 'Variable mass system : water sprayed into a moving container'
Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
Back
Top