- #1
slayerdeus
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Five identical particles of mass m = 0.30 kg are mounted at equal intervals on a thin rod of length l = 1.01 m and mass M = 2.0 kg, with one mass at each end of the rod. If the system is rotated with angular velocity = 60 rev/min about an axis perpendicular to the rod through one of the end masses, determine
(a) the kinetic energy and
(b) the angular momentum of the system.
I have KE = 1/2*Irod*w^2 + 1/2*Iparticle*w^2
= 1/2(1/3*Mass of rod + 1/2*Mass of particles)*L^2*w^2
What am I doing wrong? I haven't looked at part b yet.
(a) the kinetic energy and
(b) the angular momentum of the system.
I have KE = 1/2*Irod*w^2 + 1/2*Iparticle*w^2
= 1/2(1/3*Mass of rod + 1/2*Mass of particles)*L^2*w^2
What am I doing wrong? I haven't looked at part b yet.