Generating Chlorine from Ca(OCl)2 and HCl: 50.0g & 275 mL

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Discussion Overview

The discussion revolves around the generation of chlorine gas through the reaction of calcium hypochlorite (Ca(OCl)2) and hydrochloric acid (HCl). Participants are exploring the stoichiometry of the reaction, including the calculation of the mass of chlorine gas produced and identifying the limiting reactant.

Discussion Character

  • Homework-related
  • Mathematical reasoning
  • Technical explanation

Main Points Raised

  • One participant states that chlorine can be generated by heating calcium hypochlorite and hydrochloric acid, producing calcium chloride and water.
  • Another participant confirms that the reaction is a redox reaction but suggests that the focus should be on the limiting reagent aspect.
  • A participant attempts to calculate the moles of Ca(OCl)2 and HCl, estimating 0.35 moles of Ca(OCl)2 and 1.4 moles of HCl.
  • Another participant challenges the accuracy of the mole calculations, indicating that one of the numbers provided is incorrect.

Areas of Agreement / Disagreement

Participants do not reach a consensus on the mole calculations, with at least one participant expressing uncertainty about their estimates. The discussion remains unresolved regarding the correct values and the identification of the limiting reactant.

Contextual Notes

Participants have not provided complete calculations or clarified assumptions regarding the reaction conditions or the stoichiometry involved.

sahen
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Chlorine can be generated by heating together calcium hyperchlorite and hydrochloric acid. Calcium chloride and water are also formed.

a) If 50.0g of Ca(OCl)2 and 275mL of 6.00M HCL are allowed to react, how many grams of chlorine gas will form?

b) Which reactant will be in excess and what is its mass?


The attempt at a solution

Ca(ClO)2 + 4 HCl → CaCl2 + 2 H2O + 2 Cl2 is this a redox equation ? i don't know how to proceed. Any help would be would be appreciated ...
 
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Yes, this is redox - buit it doesn't matter. It is a (relatively) simple limiting reagent problem.

You have a correct reaction equation, calculate how many moles of both reactants you have. Which one is in excess?
 
i guess Ca(OCl)2 0.35 moles and 1.4 moles hcl is this right ?
 
Nothing to guess here, just calculate. One of your numbers is wrong.
 

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