Generating current through increasing capacitance

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The discussion revolves around calculating the current generated as a dielectric slab is inserted into a capacitor at a constant rate. The user initially derives the formula for current, I, but realizes a missing factor of "r" in their final answer. They acknowledge that dC, a differential quantity, should correspond with a differential time element, suggesting a need for clarification in their calculations. The conversation highlights the importance of correctly applying differential calculus in physics problems. Ultimately, the user seeks to understand the correct relationship between charge, capacitance, and time in this context.
Dilemma
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Hello,

1. Homework Statement

MP_Ch18_Q9_1-300x243.jpg

Assuming that the dielectric is inserted at a constant rate, find the current I as the slab is inserted.
Express your answer in terms of any or all of the given variables V, K, r, d, Δt, and ε0, the permittivity of free space.

Homework Equations


[/B]
C = ε0 * A / d

The Attempt at a Solution


[/B]
Q = CV
dQ = dC ⋅ V

I = dQ/Δt

C = ∈ ⋅ A / d = ∈⋅(xr)K / d + ∈⋅(r-x)r / d
dC = ∈⋅(r)K / d - ∈⋅r / d = ∈r(K-1)/d
dQ = dC⋅V

Therefore answer should be ∈r(K-1)V/(dΔt)

However, the correct answer is ∈(r^2)(K-1)V/(dΔt). That means the multiplier "r" is missing. What is wrong with my solution.

Thanks in advance.

 
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Dilemma said:
dC = ∈⋅(r)K / d - ∈⋅r / d = ∈r(K-1)/d
The left side is a differential quantity. So, the right side should also be a differential quantity.
 
Oops, I have forgotten to include the dx multiplier. Thank you.
 
Dilemma said:
I = dQ/Δt

dQ is a differential quantity, but Δt is the finite amount of time required to completely insert the slab.
Did you mean to write I = dQ/dt, or maybe I = ΔQ/Δt?
 
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