Generating functions with n term outside

SpartanG345
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Homework Statement



Discrete mathematics

is it possible to have a generating function where there is an n term outside the sum?

such as

2^n SUM ( bn(0.5)^n * z^n)

eg the 1st turn would be 2^n bo z^0

when you evaluate the series it evaluates to the series which i am trying to create a generating function for. NB bn is another generating function.

I also have the closed formula for bn.
 
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Assuming the sum itself is over the index n, that would be bad notation. It means the same as 2^n \sum_k (b_k(0.5)^k z^k) but NOT the same as \sum_n 2^n(b_n(0.5)^n z^n) with which it could easily be confused. On the other hand if the sum is over, say, index i from 0 to n, it would be perfectly good.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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