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icedoverfire
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Homework Statement
An individual with genotype AA Bb Cc DD Ee is testcrossed. Assuming independent assortment of all gene loci, what fraction of the progeny are expected to have genotype Aa Bb Cc Dd Ee?
Homework Equations
Crossing AA Bb Cc Dd Ee X aa bb cc dd ee
The Attempt at a Solution
With Gene A, the only possible outcome is Aa, so the probability is 1.
With Gene B, the outcome Bb is present in 1/2 of the cases.
With Gene C, the outcome Cc is present in 1/2 of the cases.
With Gene D, the outcome Dd is present in all cases, probability = 1.
With Gene E, the outcome Ee is present in 1/2 of the cases.
So multiplying all those together you get that 1/8 is the fraction with the expected genotype.
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My book does not have the answer for this problem. I am double checking my work.
Thanks,
-ice