Getting the particular solution of this differential equation.

FocusedWolf
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Homework Statement



y''-2y'-3y=-3t*e^(-t)

Homework Equations



Has to be done with method of undetermined coefficients

The Attempt at a Solution



the chacteristic equation is: c1*e^(3t) + c2*e^(-t)

my attempt at Yp is (a*t+b)*e^(-t)... so you that's not it. i tried many versions and i keep on getting a = 3t/4.

the book has the answer as y=c1*e^(3t) + c2*e^(-t)+(3/16)*t*e^(-t)+(3/8)*t^2*e^(-t)
 
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Your homogeneous equation has a solution that is of the form of one of your terms in the particular solution. I suggest a similar guess, with a tweak.
 
Since e3t is already a solution to the homogeneous equation, you need to multiply your first "guess" by t.
 
thx i successfully got the answer. At first i tried to get that to work, but then it came to the part where you got to solve for like 3 variables, like a, b, and t... and while glancing over to my calculus book, which has a better writup on differential equation then my differential equation book lol, i saw how you had to deal with this by equating the coeffecients. i don't remember this problem i posted about but it was like you had to separate it where t(a + b) + (a - b) = 3t. and did a + b = 3, and a - b = 0, and solve for a and b that way. it's interesting that that even works cause my ti89 can't do it, which is shocking lol
 
Prove $$\int\limits_0^{\sqrt2/4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx = \frac{\pi^2}{8}.$$ Let $$I = \int\limits_0^{\sqrt 2 / 4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx. \tag{1}$$ The representation integral of ##\arcsin## is $$\arcsin u = \int\limits_{0}^{1} \frac{\mathrm dt}{\sqrt{1-t^2}}, \qquad 0 \leqslant u \leqslant 1.$$ Plugging identity above into ##(1)## with ##u...
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