Golf Physics Problem: Calculate Range of Initial Velocities

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The discussion focuses on calculating the allowable range of initial velocities for a golf ball to stop within 1 meter of the cup from both uphill and downhill lies. The problem specifies constant deceleration rates of 3.0 m/s² uphill and 2.0 m/s² downhill, with a distance of 7.0 meters from the cup. Participants express confusion about the term "allowable range of initial velocities," seeking clarification on whether to calculate the range, initial velocities, or both. The solution approach involves using the equation V² = Vo² + 2a(X - Xo) to determine the extremes of the stopping distances. The results indicate that the uphill putt requires a greater initial velocity due to the higher deceleration, suggesting that downhill putts are generally easier.
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Homework Statement


In putting, the force with which a golfer strikes a ball is planned so that the ball will stop within some small distance of the cup,say,1m long or short, in case the putt is missed. Acomplishing this from an uphill lie is more difficult than from adownhill lie . to see why, assume that on a particular green the ball deccelerates constantly at 2.0m/s^2 going downhill, and constantly at 3.0 m/s^2 going hill. suppose we have an uphill lie 7.0m from the cup. calculate the allowable range of initial velocities we may impart to the ball so that it stops in the range 1.0m short to 1.0m long of the cup. do the same for downhill lie 7.0m from the cup. what in your results suggests that the downhill putt is more difficult?


Homework Equations


V^2=Vo^2+2a(X-Xo)



The Attempt at a Solution



im not sure how to approach this problem because I am not sure what it is asking me I am not sure what what"calculate the allowable range of initial velocities is? does that mean calculate the range?, initial veocities, or both?
 
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ldbaseball16 said:

Homework Statement


In putting, the force with which a golfer strikes a ball is planned so that the ball will stop within some small distance of the cup,say,1m long or short, in case the putt is missed. Acomplishing this from an uphill lie is more difficult than from adownhill lie . to see why, assume that on a particular green the ball deccelerates constantly at 2.0m/s^2 going downhill, and constantly at 3.0 m/s^2 going hill. suppose we have an uphill lie 7.0m from the cup. calculate the allowable range of initial velocities we may impart to the ball so that it stops in the range 1.0m short to 1.0m long of the cup. do the same for downhill lie 7.0m from the cup. what in your results suggests that the downhill putt is more difficult?

Homework Equations


V^2=Vo^2+2a(X-Xo)

The Attempt at a Solution



im not sure how to approach this problem because I am not sure what it is asking me I am not sure what what"calculate the allowable range of initial velocities is? does that mean calculate the range?, initial veocities, or both?

Using the numbers given in the problem calculate the extremes of the ranges (7m +/- 1m) for where the ball will end up in the equation you cited. Of course in your case Vf will be 0.

What does the range in Vi2 tell you?

Since you are imparting kinetic energy to the ball with the blade of your putter that is proportional to Vi2 then maybe you can get at what the problem is trying to relate by examining the difference between the kinetic energy needed in each case?
 
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