Grade 12 Physics - mass on an inclined plane (different question)

AI Thread Summary
A block weighing 80N on a 20-degree incline has static and kinetic friction coefficients of 0.25 and 0.15, respectively. To determine the minimum force to prevent slipping down the plane, the equations of motion in both x and y directions are used, leading to a calculated force of 46.15 N for static conditions. The difference between the forces needed to prevent slipping and to initiate movement is clarified by the direction of friction, which opposes the motion. For constant velocity up the incline, the required force is approximately 37.76 N, but the kinetic friction value should be corrected to about 11.3 N. Understanding the role of friction in both static and kinetic scenarios is crucial for solving these types of problems.
an_mui
Messages
47
Reaction score
0
A block weighing 80N rests on a plane inclined at 20 degrees to the horizontal. The coefficient of static friction is 0.25, while the coefficient of kinetic friction is 0.15.

a) What is the minimum force F, parallel to the plane that will prevent the block from slipping down the plane?
b) What is the minimum force F that will start the blocking moving up the plane?
c) What force F is required to move the block up the plane at constant velocity?

a) I am confused about the difference between question a and b? I don't know how to determine the minimum force that will prevent the block from slipping down the plane.

b) my equations

x-direction: Fapplied - Ffriction - mgsin theta = 0
y-direction: N - mgcos theta = 0
Ffriction = usN
Ff = us (mg cos theta)
Fapplied = us (mg cos theta) + mgsin theta
Fapplied = 18.79 + 27.36 = 46.15 N

N = mgcos theta

c)

Ffriction = ukN
Ff = uk (mgcos theta)
Fapplied = uk(mg cos theta) + mg sin theta
Fapplied = 10.4 + 27.36 = 37.76N

Please correct me if i made any mistakes
 
Physics news on Phys.org
actually for a:

the answer i got is:

F = mg (sin theta - ucos theta)
but other people got different answers... could someone please help me out?
 
Your answers for a) and b) are correct.
For c), check your value for the kinetic friction. It should be about 11.3.

The difference between a) and b) is in the direction that the friction acts.

Friction always opposes motion, or tendency to move.

If the block is moving in one direction, then friction is acting in the other direction.

If the block is static, then in what direction would it move if there were no friction ?
The actual friction would then act in the opposite direction to that motion.
 
Thread 'Collision of a bullet on a rod-string system: query'
In this question, I have a question. I am NOT trying to solve it, but it is just a conceptual question. Consider the point on the rod, which connects the string and the rod. My question: just before and after the collision, is ANGULAR momentum CONSERVED about this point? Lets call the point which connects the string and rod as P. Why am I asking this? : it is clear from the scenario that the point of concern, which connects the string and the rod, moves in a circular path due to the string...
Back
Top