Gradient of functions with multiple variables

Niles
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Homework Statement


The gradient of f(x,y) = x^2-x+y is:

gradient_f(x,y) = (2x-1 ; 1). To find gradient_f(x,y), I set 2x-1 = 0 and 1 = 0 - so there are no points, where gradient_f(x,y) is zero because of 1 != 0?
 
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And how to I find the maximum and minimum of the function, when there are no stationary points? (gradient_f(x,y) != 0)
 
It's been awhile since I did Calc 3, but if you're in a bounded domain, you can apply the Extreme Value Theorem. Under those circumstances, the max/min likely lie on the boundary.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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