Graphing a Polar Function: Solving for r = 2cosθ

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The polar function r = 2cosθ, when graphed for the interval -π/2 ≤ θ ≤ π/2, traces out a full circle of unit radius centered at (1,0). Initially, only the positive half-circle is observed, but understanding the symmetry of the function reveals that negative radians complete the circle. By using parametric equations derived from double angle identities, it can be shown that as θ varies, both x and y coordinates complete a full cycle. The symmetry in polar coordinates allows for the completion of the circle by simply reflecting across the polar axis. Thus, the entire graph is confirmed as a full circle.
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Homework Statement



graph the polar function r=2cos\theta (-\pi/2 \leq \theta \leq \pi/2) sorry that last theta/2 should be pi/2. new to this math text

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The Attempt at a Solution


I graphed the positive part right, I think. it seems to trace a half circle. I get confused when it comes to the negative radians. what would this trace out in full. Excuse me but its been a while since trig.
 
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You should get a full circle of unit radius, centered at (1,0). The easiest way to see that \frac{-\pi}{2}<\theta<\frac{\pi}{2} traces out the entire circle is to find parametric equations for x-1 and y and use the double angle identities. You should find that x-1=\cos(2\theta) and y=\sin(2\theta) and so as theta moves through pi radians, (x-1) and y both move through a full period, tracing out the entire circle.
 
I think an even easier way once you find part of the graph is use symmetry. If you can replace theta by negative theta then there is symmetry with respect to the polar axis and the circle is completed.
 
Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

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