Graphing Problem: Rearrange to a Straight Line Graph

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The discussion centers on a graphing problem involving mass and acceleration under a constant force, where an increasing mass results in a decreasing acceleration, leading to a negative curve. To convert this into a straight line graph, one suggestion involves using logarithmic scales, which can linearize power law relationships. However, the original poster clarifies that the curve represents deceleration rather than a negative trend, and the force is not constant as it varies with mass. They express difficulty in rearranging the equation using the formula F=ma. The conversation highlights the need for further clarification and assistance in solving the graphing issue.
dienamics
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Hi,
Was wondering if someone could help me out with this simple graphing problem.

Its a mass x acceleration graph. I have a constant force but an increasing mass e.g

When plotting this graph I end up with a negative curve, as the mass increases, the acceleration decreases.

I need to rearrange this to a straight line graph.

pls help!

Cheers.
 
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dienamics said:
Hi,
Was wondering if someone could help me out with this simple graphing problem.

Its a mass x acceleration graph. I have a constant force but an increasing mass e.g

When plotting this graph I end up with a negative curve, as the mass increases, the acceleration decreases.

I need to rearrange this to a straight line graph.

pls help!

Cheers.

A common approach is to plot logs. When you have a power law between two variables, this gives a straight line. Many plotting programs provide an option to make one or both axes a log-scale. The gradient of a log graph let's you know the power of the relationship.
\begin{align*}<br /> y &amp;= x^n \\<br /> \log y &amp;= n \log x<br /> \end{align*}​

Cheers -- sylas
 
Hmm...

Not sure that's going to work, but thats. probably should have explained the question better.

Its not a negative curve, the curve represents deceleration in the positive direction (curve with decreasing gradient) and the force is not given. If worked out using F=ma the force varies.

Not sure how to go about this one. Have tired rearranging using a=f/m but don't seem to be having much luck...

probably something really simple I'm doing wrong
 
Can anyone help me with this??:confused:
 
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