Gravitational Field Strength due to a Uniform Rod

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To calculate the gravitational field strength due to a uniform rod, it is necessary to integrate the contributions from infinitesimal segments of the rod. The variables x and dx represent the position and thickness of these segments, respectively. This approach uses calculus to sum the gravitational effects of each slice, applying Newton's inverse-square law. As the number of slices increases and their thickness decreases, the total gravitational force can be accurately determined. Understanding this integration process is crucial for mastering classical mechanics.
Quarlep
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I am trying to learn Physics an dI am reading a booK about classical mechanics.I a stuck somewhere in there If you know a gravitational force to a uniform rod I saw there a x and dx Why we need them ?

Thanks!
 
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You need to integrate the gravitational effects of infinitesimal lengths along the rod to get the total for the rod.
 
Quarlep said:
I am trying to learn Physics an dI am reading a booK about classical mechanics.I a stuck somewhere in there If you know a gravitational force to a uniform rod I saw there a x and dx Why we need them ?

That's part of the notation of calculus. If you'd tell us what the book was, we'd be certain... But chances are that they're dividing the rod into slices and using dx as the thickness of each slice and x as the position of the slice along the rod. Then the contribution of each slice can be approximated from Newton's inverse-square law and calculus provides the mathematical tools to add all the contributions up as the number of slices approaches infinity and the thickness of each slice approaches zero - and a proof that this process yields an exact answer.
 
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