Gravitational Force Between Planets

AI Thread Summary
The gravitational force between a 21.2 kg lead ball and a 442 g lead ball, separated by 10.38 cm, is calculated to be 5.8 x 10^-8 N using the formula Gm1m2/r^2. To find the ratio of this gravitational force to the weight of the 442 g ball, one must first convert the mass of the ball into weight in Newtons. The weight is calculated by multiplying the mass by the acceleration due to gravity. The ratio is then obtained by dividing the gravitational force by the weight of the 442 g ball. Understanding these calculations is essential for solving the problem effectively.
jibjab
Messages
13
Reaction score
0

Homework Statement


Part 1)
The centers of a 21.2 kg lead ball and a 442 g lead ball are separated by 10.38 cm. What gravitational force does each exert on the other?

Part 2)
What is the ratio of this gravitational force to the weight of the 442 g ball?

The Attempt at a Solution



I found part 1 - 5.8 X 10^-8 N by using the formula Gm1m2/r^2.
Part 2 I haven't the slightest idea. Does anyone know how to find the ratio?

Thanks in advance.
 
Physics news on Phys.org
To find a ratio of gravitational force to the weight of the 442 g ball, it is simply the gravitational force divided by the weight of the ball.
 
So simple and yet I couldn't get it! Thank you.
 
remember to convert 442g, a mass, into a weight in Newtons (on Earth I presume).
 
Kindly see the attached pdf. My attempt to solve it, is in it. I'm wondering if my solution is right. My idea is this: At any point of time, the ball may be assumed to be at an incline which is at an angle of θ(kindly see both the pics in the pdf file). The value of θ will continuously change and so will the value of friction. I'm not able to figure out, why my solution is wrong, if it is wrong .
TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
Back
Top