Lyphta
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[SOLVED] Gravitational Forces
A 1000 kg weather satellite is orbiting the Earth at a constant speed. It is 500 km above the Earth's surface. The Earth has a mass of 5.976 x 10^24 kg and a radius of 6370 km. (a) How much gravitational force exists between the Earth and the satellite? (b) How long does it take the satellite to go around the Earth once? (c) How are is that (measured in meters)? (d) how fast is the satellite moving (in m/sec)?
F=G(m1 m2)/r^2
C=2πr
v=rω
(a) F=6.67 x 10^-11 N.m^2/kg^2)((1000kg)(5.976 x 10^24 kg)/6870000 m^2)
= 8445.5 N
(b) I have no idea how to do this one with the numbers that was given... the answer is 94.49 min...
(c) C=2(π)(6870000 m)
= 4.32 x 10^7m
(d) all I know is to do v=rω. But I don't know what to plug in... the answer is 7617.1 m/sec
Homework Statement
A 1000 kg weather satellite is orbiting the Earth at a constant speed. It is 500 km above the Earth's surface. The Earth has a mass of 5.976 x 10^24 kg and a radius of 6370 km. (a) How much gravitational force exists between the Earth and the satellite? (b) How long does it take the satellite to go around the Earth once? (c) How are is that (measured in meters)? (d) how fast is the satellite moving (in m/sec)?
Homework Equations
F=G(m1 m2)/r^2
C=2πr
v=rω
The Attempt at a Solution
(a) F=6.67 x 10^-11 N.m^2/kg^2)((1000kg)(5.976 x 10^24 kg)/6870000 m^2)
= 8445.5 N
(b) I have no idea how to do this one with the numbers that was given... the answer is 94.49 min...
(c) C=2(π)(6870000 m)
= 4.32 x 10^7m
(d) all I know is to do v=rω. But I don't know what to plug in... the answer is 7617.1 m/sec
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