Gravity and acceleration simple calculation

AI Thread Summary
The discussion revolves around calculating the initial speed required for an object to fall from a height of 7 meters in 3 seconds, using the formula for distance under gravity. Participants clarify that the acceleration due to gravity is fixed at 9.8 m/s² and guide the calculation process, confirming that the initial speed can be derived from rearranging the distance formula. The calculation results in a negative initial speed, indicating that the object must be thrown upwards to take 3 seconds to reach the ground. Additionally, the conversation shifts to exploring how to determine the minimum initial speed needed to ensure an object covers a specified distance within a given time. The discussion highlights the complexities of motion equations and the relationship between speed, time, and distance.
forrestuv
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With this formula for distance calculation with gravity acceleration:

distance = 1/2 × acceleration × time^2 + intial speed × time

what Initial Acceleration does an object need to touch the ground in 3secs from 7meters of heigth?
what's the formula for that?

thx
 
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forrestuv said:
what Initial Acceleration does an object need to touch the ground in 3secs from 7meters of heigth?
I assume you want the initial speed, not acceleration. The acceleration of a falling body is fixed at 9.8 m/s^2.
what's the formula for that?
That formula will do. Just solve for the initial speed.
 
ops.. yes I need the initial speed..how to obtain that from the formula I posted?I'm a real noob in math :(
 
It's just a bit of algebra. Take a stab at it.

For a start, if you had A = B + C, how would you solve for C?
 
C=a-b ? :)
 
forrestuv said:
C=a-b ? :)
Exactly. So rearrange your formula accordingly.
 
distance = 1/2 × acceleration × time^2 + intial speed × time

ok so:

intial speed × time = distance - (1/2 × acceleration × time^2)

then:

initial speed = (distance - (1/2 × acceleration × time^2)) / time

is it right? :)
 
in my case:

h=7 mt
t=3 secs
g=9.8

initial speed = (distance - (1/2 × acceleration × time^2)) / time

initial speed= (h- (1/2 × g × t^2)) / t

(7-(0.5x9.8x9)) / 3

(7-44.1) / 3 = -12.3666

can you check if it is correct please ? :)
 
forrestuv said:
can you check if it is correct please ? :)
Yes, it's correct. The reason why it's negative is that you have to throw the object upwards for it to take that long to fall 7m. (If you just dropped it would take only 1.2 seconds to hit the floor.)

In your equation, you took down as positive.
 
  • #10
thxxxxxx!
I appreciated your help very very much :)
 
  • #11
Now I would like to obtain something impossible to calculate for me :)
I need to know the min Initial speed needed to have, at a certain time a distance greater than a number.

example:
if I throw a ball at an initial speed of 12 I want to be sure that at 2 secs the distance is greater than 8.
is it possible?

science fiction for me eheh :)
 
  • #12
alternatively:

Giving a fixed Initial Speed, If I want to double the distance at which the object will be at a certain time, how much should I increase time of?
 
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