Passionflower
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The energy of a test observer in a Schwarzschild solution is constant as long as it travels on a geodesic.
You can use the following equality:
\Large E=\sqrt {1-{\frac {{\it r_s}}{r}}}{\sqrt {1-{v}^{2}}} ^{-1}
So if you know the energy at one location it is very easy to calculate either the velocity or position at another location or velocity.
For instance it is easy to see that the energy of an observer free falling at escape velocity is exactly 1, just plugin vescape in the equation above.
From the energy we can get the apogee of a test radial observer, because when the velocity is zero we get:
\Large E=\sqrt {1-{\frac {r_{{s}}}{r_{{{\it ap}}}}}}<br />
Or alternatively we can get the apogee from the velocity at a given r value:
\Large {\frac {r_{{s}}}{r_{{{\it ap}}}}}=- \left( {\frac {r_{{s}<br /> }}{r}}-{v}^{2} \right) \left( {v}^{2}-1 \right) ^{-1}<br />
You can use the following equality:
\Large E=\sqrt {1-{\frac {{\it r_s}}{r}}}{\sqrt {1-{v}^{2}}} ^{-1}
So if you know the energy at one location it is very easy to calculate either the velocity or position at another location or velocity.
For instance it is easy to see that the energy of an observer free falling at escape velocity is exactly 1, just plugin vescape in the equation above.
From the energy we can get the apogee of a test radial observer, because when the velocity is zero we get:
\Large E=\sqrt {1-{\frac {r_{{s}}}{r_{{{\it ap}}}}}}<br />
Or alternatively we can get the apogee from the velocity at a given r value:
\Large {\frac {r_{{s}}}{r_{{{\it ap}}}}}=- \left( {\frac {r_{{s}<br /> }}{r}}-{v}^{2} \right) \left( {v}^{2}-1 \right) ^{-1}<br />
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