Gravity Problem Help - Find Acceleration of Gravity 3000 Miles Above Earth

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To calculate the acceleration of gravity 3000 miles above Earth's surface, the correct approach involves adding the Earth's radius to the altitude. The initial calculation of 17.1 m/s² was incorrect due to not including the Earth's radius. After correcting the distance to 11.2 x 10^6 meters, the acceleration of gravity is found to be approximately 3.17 m/s². This value is confirmed as accurate by participants in the discussion. Understanding the correct distance is crucial for accurate gravitational calculations.
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I need to find the value of acceleration of gravity 3000 miles above the Earth's surface. I figured 3000 miles = 4.83 x 10^3 meters. Mass of the Earth equals 5.98 x 10^24kg. I used the equation:

g= GM/r^2 and get 17.1 m/s^2. This is too high a value. I don't think I am using the correct distance in my calculation. Any help Please?
 
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Ok, I think I got is. I need to add the radius of the Earth which is 11.2 x 10^6 meters to the 3000 miles and the acceleration = 3.17 m/s^2 correct??
 
bengaltiger14 said:
Ok, I think I got is. I need to add the radius of the Earth which is 11.2 x 10^6 meters to the 3000 miles and the acceleration = 3.17 m/s^2 correct??
Yes, it is correct (although I think you meant 3000 miles {4828 km} plus the radius of Earth {6378 km} equaled 11.2 x 10^6 meters.)
 
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