How Do You Estimate the Standard Deviation of a Radioactive Counting Rate?

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The discussion centers around calculating the standard deviation for a counting experiment involving a radioactive sample that recorded 9934 counts in one hour. The key point is that the standard deviation in such counting experiments is determined using the formula sqrt(N), where N represents the total counts. In this case, N is approximately 10000, leading to a standard deviation of about 100. Participants emphasize the importance of understanding this statistical rule for estimating error in counting experiments, suggesting that familiarity with statistics can help derive the mean and variance of the counting distribution.
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Dear members,
here is a gre problem that I couldn't know how to tackle, any effort will be greatly appreciated.
An experimenter measures 9934 counts during one hour from a radioactive sample. From this number the counting rate of the sample can be estimated with a standard deviation of most nearly
(A) 100
(B) 200
(C) 300
(D) 400
(E) 500
the answer is (A) 100, could anyone please help me out understand this problem :confused:

thanks so much!
 
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the standard deviation in counting experiments is sqrt(N). In this case N is roughly 10000.

p.s. i have no clue why.
 
This one is more or less just remembernig the rules for estimating error.

As you probably guessed, the rule for estimating the error of a count is the square root of the count.

If you're comfortable with statistics, you could probably derive the mean and variance of the "counting" distribution (quotes because I don't remember the right name), use the observed value as an estimate of the mean, and solve for the variance.
 
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