tweety1234
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Homework Statement
Can someone please explain how my book got [itex]sin^{2} \theta = \frac{1-cos2\theta}{2}[/itex] and [itex]cos^{2}\theta = \frac{1+cos2\theta}{2}[/itex]
As I thought the half angle formula's were [itex]sin \frac{\theta}{2} = \sqrt{\frac{1-cos\theta}{2}}[/itex]
[itex]cos\frac{\theta}{2} = \sqrt\frac{1+cos\theta}{2}}[/itex]
So how can it also be the top one's aswell?
Thanks.