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Half charged spherical shell

  1. Jan 27, 2009 #1
    1. The problem statement, all variables and given/known data

    Hey guys.
    I got this question:
    "Calculate the electric field of half a spherical shell with radius R and uniform surface charge density [tex]\sigma[/tex] along its axis of symmetry above the shell."
    I guess I shell use Gauss law, the thing is that the Gauss surface will not be closed above the half spherical shell so I though about calculating the electric field for a full spherical shell and then divide it by 2 to get the electric field above the upper half spherical shell.
    What do you say? is that the way to go?

    Thanks in advance.

    2. Relevant equations



    3. The attempt at a solution
    1. The problem statement, all variables and given/known data



    2. Relevant equations



    3. The attempt at a solution
     
  2. jcsd
  3. Jan 27, 2009 #2

    LowlyPion

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    If you're talking about losing the half away from the side that is charged, I'd think not.

    From the statement I take it that the points along the axis make the charges look like concentric rings spaced at a distance according to their spherical geometry away from whatever point you are at. Like looking down at a salad bowl turned face down?
     
  4. Jan 27, 2009 #3
    Yeah, it's like a salad bowl turned face down :smile:
    I need to find a closed Gauss surface that will contain this "bowl" and I can't think of one.

    I'm sorry, I didn't understand what you mean by "If you're talking about losing the half away from the side that is charged, I'd think not.".

    Thanks a lot.
     
  5. Jan 27, 2009 #4

    LowlyPion

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    I was simply referring to your notion that you would take the integral of a whole sphere and then take away the mirror of the salad bowl.
     
  6. Jan 27, 2009 #5

    LowlyPion

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