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Half Life for patient

  • Thread starter soul5
  • Start date
  • #1
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Homework Statement



Ok so I'm doing this practise problem but I have no clue what to do.

"A radioactive sample intended for irradiation of a hospital patient is prepared
at a nearby lab. The sample has a half-life of 83.61 h. What should it's initial activity be if it's activity is to be 7.0 X 10 ^ 8 Bq when it is used to irradiate the patient for 24 h?


Homework Equations




T 1/2 = Ln2/λ

N = N0e^λt


The Attempt at a Solution



Would you just do this?


N = 7.0 X 10 ^ 8 Bq e ^(83.61 - 24)

?

please help
 

Answers and Replies

  • #2
299
0
Would you just do this?


N = 7.0 X 10 ^ 8 Bq e ^(83.61 - 24)

?

please help


Unfortunately not, start with

T1/2 = ln2/lambda
lambda = ln2/(T1/2)

and try again. Hope this helps :smile:
 

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