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Half Life for patient

  1. Apr 23, 2009 #1
    1. The problem statement, all variables and given/known data

    Ok so I'm doing this practise problem but I have no clue what to do.

    "A radioactive sample intended for irradiation of a hospital patient is prepared
    at a nearby lab. The sample has a half-life of 83.61 h. What should it's initial activity be if it's activity is to be 7.0 X 10 ^ 8 Bq when it is used to irradiate the patient for 24 h?


    2. Relevant equations


    T 1/2 = Ln2/λ

    N = N0e^λt


    3. The attempt at a solution

    Would you just do this?


    N = 7.0 X 10 ^ 8 Bq e ^(83.61 - 24)

    ?

    please help
     
  2. jcsd
  3. Apr 24, 2009 #2


    Unfortunately not, start with

    T1/2 = ln2/lambda
    lambda = ln2/(T1/2)

    and try again. Hope this helps :smile:
     
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