Hamilton function of a free particle/Landau's book

fluidistic
Gold Member
Messages
3,928
Reaction score
272

Homework Statement


The problem is taken out of Landau's book on classical mechanics. I must find the Hamilton function and the corresponding Hamilton equations for a free particle in Cartesian, cylindrical and spherical coordinates.

Homework Equations


Hamilton function: H(p,q,t)= \sum p_i \dot q _i -L where L is the Lagrangian.
Hamilton equations: \dot q_i = \frac{\partial H}{\partial p_i} and \dot p_i =-\frac{\partial H}{\partial q _i}.

The Attempt at a Solution


I'm stuck on Cartesian coordinates so far. L=\frac{m}{2}(\dot x ^2 + \dot y^2 +\dot z^2)-U(x,y,z).
p_i=\frac{\partial L}{\partial \dot q _i}=m \dot q_i \Rightarrow \dot p_i=m \ddot q_i.
H=m \dot x ^2 +m \dot y^2 +m \dot z ^2 - \frac{m}{2} (\dot x^2 + \dot y^2 +\dot z^2)+U(x,y,z)=\frac{m}{2}(\dot x ^2 +\dot y^2 +\dot z^2)+U(x,y,z). I notice that the Hamilton function is the Hamiltonian and that in this case it's worth the total energy of the system (the free particle).
However the solution given in the book is H=\frac{1}{2m} (p _x ^2+ p_y^2 +p_z ^2)+U(x,y,z). Why is it expressed under this form? I took Landau's expressions and definitions and land on a different answer... why?!

Edit: Hmm I guess it's because H should depend only on p, q and t. Never on \dot q?
 
Physics news on Phys.org
Lagrangian is a function of q, \dot{q}, and t
Hamiltonian is a function of q, p, and t

You might think that this is just semantics since \dot{q} and p are proportional to each other, but it is very important distinction.

Not sure Landau is the best book to learn these stuff from. It loves elegant solutions and hates verbose explanation.
 
Ok thanks a lot for the explanation.
By the way, about the book, do you have any other suggestion? I currently own Goldstein's 1st edition on classical mechanics. I find very few worked examples and lots of theory. So I try to complete with Landau's book.
 
Thread 'Need help understanding this figure on energy levels'
This figure is from "Introduction to Quantum Mechanics" by Griffiths (3rd edition). It is available to download. It is from page 142. I am hoping the usual people on this site will give me a hand understanding what is going on in the figure. After the equation (4.50) it says "It is customary to introduce the principal quantum number, ##n##, which simply orders the allowed energies, starting with 1 for the ground state. (see the figure)" I still don't understand the figure :( Here is...
Thread 'Understanding how to "tack on" the time wiggle factor'
The last problem I posted on QM made it into advanced homework help, that is why I am putting it here. I am sorry for any hassle imposed on the moderators by myself. Part (a) is quite easy. We get $$\sigma_1 = 2\lambda, \mathbf{v}_1 = \begin{pmatrix} 0 \\ 0 \\ 1 \end{pmatrix} \sigma_2 = \lambda, \mathbf{v}_2 = \begin{pmatrix} 1/\sqrt{2} \\ 1/\sqrt{2} \\ 0 \end{pmatrix} \sigma_3 = -\lambda, \mathbf{v}_3 = \begin{pmatrix} 1/\sqrt{2} \\ -1/\sqrt{2} \\ 0 \end{pmatrix} $$ There are two ways...
Back
Top