I Hamiltonian of a Physical Theory: Lagrangian vs Transformation

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A Hamiltonian formulation of a physical theory can be derived from its Lagrangian form through the Legendre transform, provided the Lagrangian is a convex function of the generalized coordinates' time derivatives. The existence of the Legendre transform is not guaranteed in all cases, which can complicate the transition between formulations. Specific examples can illustrate these concepts, but the general requirement for convexity is crucial. Misunderstandings about the universality of the Legendre transform can lead to confusion in theoretical applications. Understanding these distinctions is essential for accurately applying Hamiltonian mechanics.
Narasoma
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What does it means for a physical theory to have hamiltonian, if it is formulated in lagrangian form? Why doesn't someone just apply the lagrangian transformation to the theory, and therefore its hamiltonian is automatically gotten?
 
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Can you be more specific and give a specific example?

In general, you can get to the Hamiltonian formulation of the same theory by applying the Legendre transform (which is what I assume that you mean) to your Lagrangian. In order for this to work, the Legendre transform needs to exist, which in turn requires the Lagrangian to be a convex function of the time derivative of your generalised coordinates.
 
Orodruin said:
Can you be more specific and give a specific example?

In general, you can get to the Hamiltonian formulation of the same theory by applying the Legendre transform (which is what I assume that you mean) to your Lagrangian. In order for this to work, the Legendre transform needs to exist, which in turn requires the Lagrangian to be a convex function of the time derivative of your generalised coordinates.
Ah, sorry. Legendre transformation. That was what I meant. But doesn't it always exist?
 
Narasoma said:
Ah, sorry. Legendre transformation. That was what I meant. But doesn't it always exist?
No. See the wikipedia page.
 
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