Hammer Projectile Motion: Time and Range Calculations.

AI Thread Summary
The discussion focuses on a physics problem involving projectile motion where a hammer slides down a roof at a constant speed of 4 m/s from a height of 10 m at a 30-degree angle. The calculated time to hit the ground is approximately 1.239 seconds, and the horizontal range is about 4.291 meters. A correction is noted in the equation used for vertical motion, emphasizing the need for the term .5gt^2 instead of .5gt. The calculations for both time and range are verified as correct, confirming the accuracy of the solution. Understanding these principles is essential for solving similar projectile motion problems.
joemama69
Messages
390
Reaction score
0

Homework Statement



A worker on the roof of a house drops his hammer, which slides down the roof at a constand speed of 4 m/s. The roof makes an angle of 30 degrees with the horizontal, and its lowest point is 10 m from the ground.

A-find the time it takes to hit the ground
b- what is the range

Homework Equations



v(x) = 4cos-30 = 3.464
v(y) = 4sin-30 = -2

The Attempt at a Solution



Just want someone to verify my work

y = y(initial) + v(y)t + .5gt
0 = 10 - 2t - 4.9t, t = 1.239s

x = x(initial) + v(x)t
x = 3.464(1.239) = 4.291 m
 
Physics news on Phys.org
Your solution is correct.
But in the equation
y = y(initial) + v(y)t + .5gt
it should by
y = y(initial) + v(y)t + .5gt^2
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top