Harmonic Oscillator kinetic and potential energies

AI Thread Summary
In a simple harmonic oscillator with total energy E, the kinetic and potential energies when the displacement is three-fourths the amplitude are calculated as KE = 7/16 E and PE = 9/16 E. For the scenario where kinetic energy equals half of the potential energy, the displacement can be determined using the relation x = √(2/3)A, which approximates to 0.8165A. The initial answers provided by the user were incorrect according to their quiz feedback, leading to confusion. The discussion emphasizes the importance of correctly applying the formulas for kinetic and potential energy in harmonic motion. Understanding these calculations is crucial for solving related problems accurately.
lydster
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A simple harmonic oscillator has a total energy of E.

(a) Determine the kinetic and potential energies when the displacement is three-fourths the amplitude. (Give your answer in terms of total energy E of the oscillator.)

Kinetic energy ______________ x E <----(times E)

Potential energy _____________ x E <-----(times E)(b) For what value of the displacement does the kinetic energy equal one half the potential energy? (Give your answer in terms of the amplitude A of the oscillator.)_________________ AI followed an example from the book, which was the same question, except for A and B it was one-half, and their answers are for (a) Kinetic is 3/4 E and potential is 1/4 E. and I have no clue on B

Thanks
 
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lydster said:
A simple harmonic oscillator has a total energy of E.

(a) Determine the kinetic and potential energies when the displacement is three-fourths the amplitude. (Give your answer in terms of total energy E of the oscillator.)

Kinetic energy ______________ x E <----(times E)

Potential energy _____________ x E <-----(times E)(b) For what value of the displacement does the kinetic energy equal one half the potential energy? (Give your answer in terms of the amplitude A of the oscillator.)_________________ A

I followed an example from the book, which was the same question, except for A and B it was one-half, and their answers are for (a) Kinetic is 3/4 E and potential is 1/4 E. and I have no clue on B
I don't think those answers are right.

The potential energy for a harmonic oscillator is:

PE = \frac{1}{2}kx^2

The total energy is the PE when KE=0 which occurs at maximum amplitude. ie total E is:

E = \frac{1}{2}kA^2

So KE = E - PE = \frac{1}{2}k(A^2 - x^2) = \frac{1}{2}kA^2(1 - (\frac{x}{A})^2) = E(1 - (\frac{x}{A})^2)

where x is the displacement and A is the maximum amplitude.

So for a), if displacement is 3/4 of A, then KE = 7/16 of E and PE is 9/16 of E

For b) if KE = .5PE, then PE = E/1.5 = 1/3kA^2. You can work out the displacement from that.

AM
 
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answers

Yeah I got a friend to try those numbers, and they didn't work out. He got the same answers as you, and they are wrong. Hmmmm...I dunno. Everything that you said makes sense
 
lydster said:
Yeah I got a friend to try those numbers, and they didn't work out. He got the same answers as you, and they are wrong. Hmmmm...I dunno. Everything that you said makes sense
What makes you think the 7/16 , 9/16 answer is wrong?

The answer to b), if kA^2/3 = kx^2/2 then

x = \sqrt{\frac{2}{3}}A = .8165A

What does your book say?

AM
 
Because my online quiz thing automatically says if I'm right or wrong, and those answers were off. It said that I was within 10%-100% of the actualy answer. My book doesn't really say anything on that.
 
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